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1. Six consecutive whole numbers are given. The sum of the first three numbers is 27. What is the sum of the last three numbers?
- A. 36
- B. 36
- C. 36
- D. 36
Answer: Option A
Explanation:
Let,
Numbers are n, n + 1, n + 2
ATQ,
n + n + 1 + n + 2 = 27
Or, 3n + 3 = 27
Or, 3n = 24
Or, n = 8
So, the numbers are - 8,9,10
Now, the last 3 consecutive numbers are 11,12,13
Sum of them 11 + 12 + 13 = 36
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